0=-(3+2xy+y^2)

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Solution for 0=-(3+2xy+y^2) equation:


Simplifying
0 = -1(3 + 2xy + y2)
0 = (3 * -1 + 2xy * -1 + y2 * -1)
0 = (-3 + -2xy + -1y2)

Solving
0 = -3 + -2xy + -1y2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2xy' to each side of the equation.
0 + 2xy = -3 + -2xy + 2xy + -1y2
Remove the zero:
2xy = -3 + -2xy + 2xy + -1y2

Combine like terms: -2xy + 2xy = 0
2xy = -3 + 0 + -1y2
2xy = -3 + -1y2

Divide each side by '2y'.
x = -1.5y-1 + -0.5y

Simplifying
x = -1.5y-1 + -0.5y

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